- How could "probability density" be measured? Consider an
imaginary device which, on command, produces an electron in a particular wavefunction
. We have the device produce an electron in this
particular state and then measure the electron's position. Of course, we get
different answers every time we use the device: position would be
a "random variable". This file
contains the results of 1000 position measurements. (I've sorted the
position measurements: from highest to lowest-- repeated measurements
of position would produce patternless results.) Your job is to
plot the probability density as a function of position. A complete
answer would include estimates of the probability density
(with error!) at various positions.
- We have used the energy and length scales: e and l
and the related time and momentum scales (/e and
/l).
- Show that classical equation of motion:
z(t)=z0-½gt2
becomes:
z'(t')=z'0-t'2
in our dimensionless variables.
- Using the data on p.6 show that this is in fact how the
expectation value of position is moving.
- Show that the dimensionless variables behave as if m=½
in that for example, if the dimensionless momentum p'=1,
the dimensionless velocity (length/time) v'=2 and the
dimensionless kinetic energy is 2.
- Heisenberg's uncertainty principal states that the product of
uncertainties in x and p must be hbar/2 or more:
Find z' and p'
for the eigenfunctions: n=1,2,4,8,16. (Hint: the p' operator is
just -i × the derivative w.r.t. z'; of course it's hermitian).
Plot the uncertainty product
vs n. What seems to be the relationship between the two.
Explain.
- Look up the virial theorem in a quantum mechanics textbook; prove
the result and show how the general result proves what we needed in
the perturbation theory section.
- The actually infinite potential for z<0 is not
physically possible. If we replace that potential with more
possible potentials, how will the eigen-energies and functions change?
If the Schrödinger's equation with the replacement potential can be
solved, then what is required is to match those solutions for
z<0 with the Airy functions for z>0.
The easiest solution for Schrödinger's equation
(see example ½) is the
constant potential: V(z')=V0. If
E<V0, we still have a turning point at
z=0, i.e., the ball will still bounce up from the floor. Of course,
it will "tunnel" a bit into the classically disallowed region of
z<0; in fact the solution to Schrödinger's equation
is just an exponential: =exp(z')
where =(V0-E')½.
Matching the wavefunctions at z'=0 amounts to equating
the "logarithmic derivative" of the wavefunction:
at z'=0-
to the same at z'=0+, i.e.,
The below displays the resulting energy shifts if V0=10
(black energy levels are for infinite potential, red for finite [10]
potential).
Pick some value for V0 and calculate the
the energy levels for that modified potential.
- Another possible choice for the z<0 potential is
another linear potential, this time one producing a constant (and much
larger) upward force. The solution for the z>0
remains: Ai(z/lR-E/eR) with
eR and lR as appropriate
for z>0, and Ai(-z/lL-E/eL) with
eL and lL as appropriate
for z<0. Matching the "logarithmic derivative" of the wavefunction:
at z'=0-
to the same at z'=0+, i.e.,
where x is E/eR.
In the particular case that the force on the left is 27 times
the force on the right: lL=lR/3
and eL=9eR. The resulting energy
levels are displayed in red below (black is the usual infinite potential
case).
Pick some value for the left-side force and calculate the
the energy levels for that modified potential.
- The above equation for the energy is simplified if the left-side
force equals (in magnitude) the right-side force. The only solutions
are Ai(-x)=0 and Ai'(-x)=0. The former are
solutions with odd symmetry. For that reason these solutions
have =0 at z=0, and hence are identical
(on the rhs) to our usual infinite-potential solutions. The latter are solutions
have even symmetry. The even and odd solutions alternate with
the even ground state at E'=1.019.
Make a stacked wavefunction plot of the first 5 energy eigenfunctions
for this symmetric two-force problem (i.e., with V=|z'|).
Be sure to include the plot of potential energy on this same plot.
- The bouncing ball is known to be in the n=16 state when the
infinite potential is removed and replaced with a lhs force identical
in magnitude (but pushing up) to that on the rhs. Find the 7 states
in which the bouncing-ball is now mostly likely to be found. Calculate
the weighted average and standard deviation of those energies. Must
we observe that the particle's energy is conserved? Using those 7 states
(with proper time dependence), plot the position-probabilities for several
times near when the infinite potential is removed, and for a time one
classical period (in the two-force situation) and ½ classical period
after the infinite potential is
removed. (It's easiest to plot the z'<0 and z'>0
separately.)
- Reproduce the falling ball solution described on p.7 with some other
initial wavefunction. Produce plots and tables showing the results.
- WKB
- Why is it N+¾ rather than N+½?
- The falling QM ball is based on a energy eigenfunction with E' near 122.2.
Find more significant digits for the energy and determine what n has this
energy.
- In the case of the 27× lhs force, the energy of the 10th state is about:
12.2842. What would WKB predict (i.e., do WKB for two-sided linear case)?
- Find the WKB approximation for the energy in the symmetric two-force
situation.
- Rayleigh-Ritz
- Confirm the reported results for f(z')=z' exp(-az').
- Find the RR estimate for the groundstate energy using
f(z')=z' exp(-az'2).
- Find the RR estimate for the groundstate energy using
f(z')=z' exp(-az'3/2).
- Pick your own f(z').
- Plot the above four wavefunctions along with the exact Airy function solution.
- Rayleigh-Ritz. There is no reason to limit the number of adjustable
parameters in our trial wavefunction (other than that it then becomes a more
difficult problem to find the minimum). Pick a trial wavefunction with
with two adjustable parameters (e.g.,
f(z')=z'(1+bz'2) exp(-az'2) )
and find the expectation value for H as a function of the two parameters
(e.g., a and b). Make a contour plot of the result to
identify an approximate best value and then use Mathematica's FindMinimum or
similar program to get the best possible RR bound. Plot the resulting wavefunction
along with the exact wavefunction.
- Perturbation Theory: Consider a perturbing potential which for
0<z'<a is V'=a-z', and otherwise V'=0.
This results in a total potential that is constant (total P.E.=a)
if 0<z'<a
and exactly equals our old potential otherwise.
The above total potential
can be "easily" solved. For 0<z'<a
Schrödinger's equation solution is
sin(kz') where k2=E'-a. For z'>a,
we have our usual Airy solutions: Ai(z'-E'). As usual we find eigenenergies
by solving the equation that comes from matching the logarithmic derivatives
at z'=a.
The below plot shows how the energy levels for n=1,2 change as
a function of a. Note that perturbation theory tracks the exact result
until about a=1.5 for n=1 and a=3.5 for n=2.
Note that in both cases the perturbation theory result is a bit above the exact result.
- Pick some value of n and plot how perturbation theory tracks the
exact result.
- For any problem we are guaranteed that the perturbation theory result
for the ground state lies above the exact result. Why?
- Second order perturbation requires an infinite sum of numerical integrals, and
is therefore hard to calculate completely. Calculate the second order correction for
a=2 and n=1 including terms through n=10. Compare
to the exact result.
- Consider the displacement operator, Dc, defined by:
Dc f(x) = f(x+c)
- Show that Dc is a linear operator.
- Find the inverse of Dc. Find the
Hermitian conjugate of Dc. Is Dc
Hermitian? Unitary? etc.
- Show that
Dc f(x) = exp(i pc/) f(x)
where p is the momentum operator, is Taylor's expansion.
Using this equation, find the Hermitian conjugate of Dc.
- Carefully show that Dc commutes with the derivative operator
d/dx (and hence [Dc, p] = 0).
- Consider the 1-d Hamiltonian H for the
linear potential U=z for all z, even z<0.
Show:
[H,Dc] = -c Dc
Use this relationship to show that if is an
energy eigenfunction with energy E, then Dc
is an energy eigenfunction with energy E-c.
(This problem is important in the usual treatment of raising and lowering operators in SHM.
See any QM textbook -- my treatment on SHM p.8 is intensionally unusual.)
- Show that state Dc is normalized if
is normalized. (In the usual treatment of lowering operators
one finds that repeatedly lowering a state must eventually produce a zero-normed
state.)
- On these pages we made a "2d" falling problem by adding a force-free dimension (y)
to a constant-force dimension (z). Another option would be to make the
y dimension also have a constant-force (but perhaps with a different strength
force than in the z direction). In this case the constant force F would be constant
but with different components in the y and z directions. We might as
well orient the force in the vertical direction by rotating our axes. Thus:
- Solve Schrödinger's equation in this case, reporting the eigenenergies
and wavefunctions in terms of the normal (dimensioned!) variables
(like y, z, Fy, Fz,
m, ).
- Write down the ground state energy as a function of
for fixed |F|.
- Since we observe energy differences as emitted photon energies, energy
differences are in some sense more fundamental than energies.
Plot both the ground state energy and the first excited energy
as a function of so you can see how the energy difference
depends on .
- Consider the cases =45° and 30°. Calculate
the energies of the lowest 8 eigenstates. Plot the results.
For comparison, the above is an example of the Newtonian trajectory for this
potential...follow the bouncing ball!
- In the above problem you have found the eigenenergy of various states as
a function of . Consider the effect of a small
change in in first order perturbation theory, i.e.,
U = cos z + sin y
U' = (-sin z + cos y)
Compare the results of perturbation theory to the exact result.
- Show that is the standard deviation of the
wavefunction:
= N exp(-y'2/42)
exp(i k0y')
What is the mean position? Find the mean momentum of this wavefunction
and the standard deviation of the momentum. What is the value of the Heisenberg Uncertainty
product in this case?
- On page 11 I claimed that the following
is a solution to the time dependent Schrödinger's equation:
Prove this. Show also that the final "quantum cannon" wavefunction
is a linear combination of terms like the above and hence
also a solution to the time dependent Schrödinger's equation.
- On page 11. I commented:
I claim that this kind of messy solves
our time-dependent Schrödinger's equation. This task
is left for a problem.
where the reference is to the force-free motion in in the y
direction of the 2d fall, which was derived as follows:
Starting with the last formula, show directly (perhaps using Mathematica)
that this is a solution to the time-dependent Schrödinger's equation.
- Using your own words define group velocity and phase velocity.
Consider the following sequence of pictures taken at t=0, 0.1, 0.2, 0.3, ..
(this appeared on page 12).
Use these plots to calculate the phase and group velocity
displayed in this packet.
- Using the graphs on page 13 estimate
the average z position of the wave-packet at the various times.
Enter the data into a fitting program and fit the data to the expected
quadratic:
z(t)=z0+v0t+½at2
Compare the fit parameters to those expected from the construction of the
wave-packet.
- Following the methods on page 13 find
bn that approximate some other initial wavefunction.
- Combine your above wavefunction with a y wavefunction
to fire the quantum cannon using your initial conditions.
- Provide the missing steps for these results from page 13.