can, with some work, be seen to solve the equation of motion:

Start by noting that the velocity vector is made of a constant
vector (*e**v*_{0}**j**)
added to the red rotating vector. Taking the time derivate removes
the constant from consideration, so the acceleration vector must
be tangent to the circle--i.e., rotated 90° from the red radial
vector, which is itself rotated 90° from **r** (note
that the zero for was the *x*-axis for
the orbit and the *y*-axis in the hodograph). Thus
the acceleration vector is in the right direction: -**r**.
The magnitude of the acceleration vector is just:

is related to the
(constant) angular momentum (*L*) [which we can
evaluate for example, at the near point].

Solving the above for and substituting into our equation for the magnitude of the acceleration vector, yields:

Note in passing that if the angular momentum is zero,
then *e*=1. The circular orbits (*e*=0)
have the maximum possible angular momentum for a given semi-major axis
*a*, that is for a given energy *E* because
there is a simple relation between the semi-major axis *a*
and *E*:

Note that the energy is negative; the positive kinetic energy equals (on average) one half the absolute value of the potential energy (the Virial theorem again!) and the result is that the total energy is ½ the average potential energy.

Here is another way of presenting the results: plots displaying the position of the particle on the orbit and the velocity of the particle on the hodograph at a series of equally spaced times.

The above is a plot of the (*x,y*) location of
a electron (or planet) at successive increments of time (tics)
Note the when the electron (planet) is close to the nucleus (or Sun),
the particle seems to move a great distance between tics, whereas
when the particle is is far from the origin, it seems to move
only a little between tics. This is exactly what you would
expect for a particle conserving angular momentum (i.e., following
Kepler's second law of constant areal velocity).

The above is a plot of the (*v _{x},v_{y}*)
velocity of
a electron (or planet) at successive increments of time (tics)
Note the when the electron (planet) is close to the nucleus (or Sun)
(e.g., near tic 0)
the velocity seems to change quite a bit between tics, whereas
when the particle is is far from the origin
(e.g., near tic 25), the velocity seems to change
only a little between tics. This is exactly what you should expect
for a 1/

Note that the motion is confined to a plane so we can display the results on a flat screen.

If we ignore the angular part of the motion, we can make plots of the
the radial velocity vs. time (in tics),
the distance from the origin (*r*) vs. time, and
the speed (*v*) vs. time:

Note that *r* seems to "bounce" off the minimum radius
*r*_{min}. The motion is in fact quite similar to the
bouncing falling ball. Here *v*_{r} changes quickly
(but not instantaneous) between negative (falling) and positive (rising)
values. The green area on the *r* plot shows the classically
allowed region.

Things happen fast during the "bounce" when the electron is near the nucleus, i.e., when the forces are large. Here are the details:

Note that while *r* does range between two values:
*r*_{min}= *a*(1-*e*) &
*r*_{max}=*a*(1+*e*),
these turning points are a bit different from our 1-d
turning points as *v* is never zero.
We can, however, threat our 3-d (reduced to 2-d) motion
as a 1-d motion in an
effective potential (see for example, Marion p.301, Barger & Olsson p.138,
Goldstein p.61) which includes the centrifugal potential:

The above diagram plots various the energies involved
as a function of *r*. The
line representing "Total Energy" is flat, because total energy is
conserved (i.e., is constant).
Total energy is the sum of
kinetic energy and potential energy. We can decompose
kinetic energy (½*mv*^{2}) into two pieces
by using the Pythagorean theorem to decompose *v*^{2} into the sum of two terms:
radial velocity squared (*v*_{r}^{2})
and the component of velocity perpendicular to **r**
("transverse" velocity) squared. The
"transverse" kinetic energy, can be calculated from the
angular momentum and *r*...the result is the centrifugal potential.
The centrifugal potential has
been added to the 1/*r* potential; the result is plotted
in red.
Thus total energy is the sum of the effective potential and
the "radial" kinetic energy. At the turning points there
is zero "radial" kinetic energy, and the
radial velocity is zero (i.e., the particle is no longer moving in
or out: *r* is either at a minimum or a maximum).
We note that for orbital motion, the time to complete
a radial oscillation :

(i.e., *r*_{min}*r*_{max}*r*_{min})
is also the time it takes to go around the Sun
(i.e., for to increase by 2).
[In the case of the 2-d oscillator, the radial period was one half
the period. In general there is no relationship
between the two periods; as a result the orbit is not a closed figure.]